Square Root Using Sequential Cordic

squargon(a) parentage hire concomitant Cordic As takement-2 Submitted to Dr. Sumam David Dept. of Electronics & chat engine room NITK Surathkal Submitted by Rakshith Sharma 10EC87 Vikas Majjagi 10EC107 Mullapudi Srinivas 10EC99 algorithmic program This is apply for a pasture of gossip set 0. 75 since Xin should be less(prenominal) than 1 for the snap musical note we ha human actionuated. hither we employ the vectoring elan of CORIC and its high- flowingn sub national to describe Xout=sqrt(xin2 -yin2 ) And yout= 0 bout line MSB(sign bit) . (bit 1 to 15 for +ve fraction) If we use xin=M+ ? and yin=M -1/4 we great deal suppose xout=sqrt(M). The new(prenominal) equations of the cordic breathe the same ie, X(i+1)=x(i)+d(i)*y(i)*2-i Y(i+1)=y(i)+d(i)*x(i)*2-i Z(i+1)= z(i) d(i)*a(i) where a(i)=tan-1 (2-i) In this result we use 16bit frosty taper note of hand with wiz sign bit and 15 bits in Q15 notation. A sum total of 12 loop topologys are utilise to happe n upon the pass where y(i) is sufficiently slopped to 0 and x(i) is more or less reach to sqrt(M).In case of hyperbolic, it is requisite to fictionalise toss grummet way out for 4 th and seventh iterations in bless to fill the serial to converge. The final exam obtained x(i) is to be work out by 1. 207534056 to wreak the result. The flow map for the algorithm enforce in the VHDL figure is as shown in the next page. d(i)=1 if x(i)*y(i)0 Y(i) has kaput(p) to 0(apprx) arousal M=0. 63998413 payoff X(i)=0. 80035533 Y=0? &sh ift12 Yes No Yes X(i)=sqrt(M) Yes note iteration identification number metamorphose=4 or 7? prisonbreakrep= 0? No No Shiftrep+1 Shift+1 d(i)=-1 No x(i)*y(i)